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CBSE Class 11-science Answered

A person moves 30 m north, then 20 m east then 30 root 2 m south west. His displacement from the original position is
Asked by Anil | 28 May, 2017, 06:09: PM
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The path of the particle is shown in the following figure.
 
 
begin mathsize 12px style From space the space figure comma straight y squared equals 30 squared plus 20 squared straight y squared equals 1300 straight y equals square root of 1300 equals 10 square root of 13 space straight m Hence comma space the space displacement space is space AD AD equals 30 square root of 2 minus 10 square root of 13 equals 42.42 minus 36.06 AD equals 6.36 space straight m end style
 
Answered by Romal Bhansali | 29 May, 2017, 10:36: AM

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CBSE 11-science - Physics
1. Explain path length and displacement with illustrations and distinguish them. 2. Define uniform velocity of an object moving along a straight line. What will be the shapes of position-time and velocity-time graphs of such a motion? Find the distance travelled by the uniformly accelerated object in one dimension in nth second. Draw velocity-time graph of a uniformly accelerated motion in one dimension and explain that the distance travelled is equal to the area under velocity-time graph. ted motion deduce the equations of motion in (i) From the velocity-time graph of uniform accelerated motion. velocity and time (ii) distance and time (iii) distance and velocity. Show that the vector addition of two vectors is different from scalar addition of two scalars. 7. What vectors. zero vector? How can you obtain zero vectors? Give examples and properties of zero It is easier to pull than to push a lawn roller. Explain with diagram. State triangle law vector. vector addition. Find analytically the magnitude direction resultant 10. State parallelogram law of vector addition. Find analytically the magnitude and direction of resultant vector, when (i) two vectors other. parallel to each-other (ii) two vectors perpendicular to each- 11. What a projectile? Give its examples. Show projected horizontally from a certain height.
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