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A person goes to his office from his home daily at a fixed speed but today he decided to reduce his speed by 20% as a result he reaches his office 16 minute late. what's the actual time he takes to reach his office daily
Let u be the fixed speed of travel and d be the distance between home and office.

Normal time of travel = distance / speed = d/u

If speed is reduced to 20%, then reduced speed = ( u - 0.2 u ) = 0.8 u

time of travel with reduced speed = d / ( 0.8 u )

time difference = [ d / ( 0.8 u ) ] - ( d/u ) = 0.25 × (d/u )

if time difference is 16 minute, then normal time of travel (d/u) is calculated as

0.25 × (d/u ) = 16 min

(d/u) = 64 min
Answered by Thiyagarajan K | 25 Sep, 2022, 08:07: PM

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