a particle moves in the x-y plane under the action of a force F such that the value of its linear momentum (P) at any time T is Px=2cost, Py=2sint .The angle ? between P &F at the time T will be?

Asked by  | 3rd Dec, 2012, 03:29: PM

Expert Answer:

using second law of motion, force is rate of change of momentum.
thus Fx = d(Px)/dt = -2sint
Fy = d(Py)/dt = 2cost
thus angle between them can now be calculated using vector algebra at time T as:
angle theta = tan-1 (|F|/|P|)

Answered by  | 10th Dec, 2012, 09:14: PM

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