a particle moves in the x-y plane under the action of a force F such that the value of its linear momentum (P) at any time T is Px=2cost, Py=2sint .The angle ? between P &F at the time T will be?

using second law of motion, force is rate of change of momentum.

thus Fx = d(Px)/dt = -2sint

Fy = d(Py)/dt = 2cost

thus angle between them can now be calculated using vector algebra at time T as:

angle theta = tan^-1 (|F|/|P|)