a particle is projected from ground with an initial velocity of 20 m per sec at an angle of 30 degree with the horizontal. wht is magnitude of change in 0.5 sec?

Given, u = 20 m/s

          θ = 30^₀

Assuming that your question was about change in magnitutde of Velocity, we can say

 

u_x = u cosθ = 20xcos30 = 20x = 10m/s

u_y = u sinθ = 20xsin30 = 20x1/2 = 10 m/s

 

a_x = 0 m/s²

a_y = -g = -10 m/s²

 

Now change in velocity after 0.5 seconds is,

 

v_x = u_x + a_xt = 10 + 0 = 10 m/s

v_y = u_y + a_yt = 10 + (-10x0.5) = 10-5 = 5 m/s

 

So, the magnitude of final velocity after 0.5 seconds is, v =

therefore, v =

                 =

                 =

                 = 18.03 m/s

 

Team,

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