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a particle is projected from ground with an initial velocity of 20 m per sec at an angle of 30 degree with the horizontal. wht is magnitude of change in 0.5 sec?
Asked by dharya21 | 03 Jul, 2010, 12:00: AM
Given, u = 20 m/s
θ = 300
Assuming that your question was about change in magnitutde of Velocity, we can say

ux = u cosθ = 20xcos30 = 20x = 10m/s
uy = u sinθ = 20xsin30 = 20x1/2 = 10 m/s

ax = 0 m/s2
ay = -g = -10 m/s2

Now change in velocity after 0.5 seconds is,

vx = ux + axt = 10 + 0 = 10 m/s
vy = uy + ayt = 10 + (-10x0.5) = 10-5 = 5 m/s

So, the magnitude of final velocity after 0.5 seconds is, v =
therefore, v =
=
=
= 18.03 m/s

Team,
Topper Learning
Answered by | 19 Jul, 2010, 11:32: AM

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