CBSE Class 11-science Answered
a car moving with a velocity of 20m/s stopped in a distance of 40 m . if the same car is travelling at double the velocity the distance travelled by it for same retardation is?
Asked by julianabalaswamy762 | 06 Apr, 2020, 05:27: PM
Expert Answer
Initial velocity of car, u = 20 m/s
The final velocity will be, v= 0 as the car comes to rest after travelling distance of 40 m (which will be after application of brakes)
By third equation of motion we know,
v2 = u2 + 2 as
0 = (20)2 + 2 x a x (40)
- 80 a = 400
Thus, a = - 5 m/s2
Negative sign indicates that it is a retardation.
When same car is moving with double the velocity
Initial velocity, u = 2 x 20 =40 m/s
Thus,
0 = (40)2 x 2 x (-5) x s
10 s = 1600
s = 160 m
Hence, if the same car is travelling at double the velocity the distance travelled by it for same retardation is 160 m
Answered by Shiwani Sawant | 06 Apr, 2020, 06:08: PM
Concept Videos
CBSE 11-science - Physics
Asked by manjusrihalder395 | 07 Jan, 2024, 09:55: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by spandya632 | 17 Nov, 2023, 08:36: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by hy9022075 | 10 Jan, 2023, 09:06: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by ad4957216 | 03 Jan, 2023, 04:54: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by prashantgaikwadfox000 | 25 Sep, 2022, 05:38: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by ukalyadab | 18 Jul, 2022, 11:52: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by piyushhoney2006 | 20 Jun, 2022, 04:12: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by chinttubabu9692 | 27 Jan, 2022, 06:37: PM
ANSWERED BY EXPERT