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# CBSE Class 10 Answered

A battery of 5V and internal resistance 1ohm is connected to a combination 8ohm and 11ohm connected in series with each other. Calculate the current in the circuit.
Asked by nibedita.behera.0308 | 20 Apr, 2019, 11:02: AM
P.D = 5 V
Internal resistance (r) = 1 Ω

Resistance in circuit,
8 Ω and 11 Ω resistors are connected in series,

Thus, Rs = 8 + 11 = 19 Ω
Thus total resistance in circuit = 19 +r =19 + 1 = 20 Ω

By Ohm's law,
I = V/R
I = 5/20 = 0.25 A

Thus, total current flowing through circuit is 0.25 A.
Answered by Shiwani Sawant | 20 Apr, 2019, 01:53: PM

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