CBSE Class 11-science Answered
17th?
![question image](https://images.topperlearning.com/topper/new-ate/15732335128401NewDoc2018080411.jpg)
Asked by smanishkumar2002 | 04 Aug, 2018, 20:34: PM
According to the question,
let ABC is an equilateral triangle with equation of BC x + y = 2 and vertex A (2, -1).
First we will find the perpendicular distance from vertex A on BC such that AD is perpendicular to BC.
![begin mathsize 16px style open vertical bar fraction numerator straight x plus straight y minus 2 over denominator square root of 1 plus 1 end root end fraction close vertical bar equals open vertical bar fraction numerator 2 minus 1 minus 2 over denominator square root of 1 plus 1 end root end fraction close vertical bar equals fraction numerator 1 over denominator square root of 2 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/d6288951ffa7e6dde008baa7c31498b7.png)
In ΔADB,
![begin mathsize 16px style sin 60 degree equals fraction numerator square root of 3 over denominator 2 end fraction
AD over AB equals fraction numerator square root of 3 over denominator 2 end fraction
fraction numerator begin display style fraction numerator 1 over denominator square root of 2 end fraction end style over denominator AB end fraction equals fraction numerator square root of 3 over denominator 2 end fraction
AB equals fraction numerator 1 over denominator square root of 2 end fraction cross times fraction numerator 2 over denominator square root of 3 end fraction equals fraction numerator 1 over denominator square root of 6 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/405b05a275cf250a9fcaf00fe591cbf1.png)
Answered by Sneha shidid | 06 Aug, 2018, 10:56: AM
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