CBSE Class 12-science Answered
Two positive point charges of 0.2 μC and 0.01 μC are placed 10 cm apart. Calculate the work done in reducing the distance to 5 cm.
Asked by Topperlearning User | 22 Apr, 2015, 02:07: PM
Expert Answer
Given:
q1 = 0.2 μC
q2 = 0.01 μC
r1 = 10 cm = 0.1 m
r2 = 5 cm = 0.05
Work done in reducing the distance from 10 cm to 5 cm can be calculate by using the relation
Answered by | 22 Apr, 2015, 04:07: PM
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