CBSE Class 12-science Answered
1) Five identical capacitors, each of capacitance C are connected between points X and Y as shown in the figure. If the equivalent capacitance of the combination between X and Y is 5mF. Calculate the capacitance of each capacitor.
2) Eight identically charged drops are joined to form bigger drop. By what factor the charge and potential change?
Asked by hitanshu04 | 28 May, 2021, 10:27: PM
Expert Answer
Unable to solve first question because figure is not posted.
Second question :-
Charge is always conserved .
Hence charge q present in 5 identical drops will be accumulated as 5q in the final drop.
if r is the radius of small drop , then radius of final drop is determined by equating volume
5 × (4/3 ) π r3 = (4/3) π R3
Hence , R = 51/3 r = 1.71 r .....................................(1)
Total potential of 5 drops , Vi = 5 × K × (q/r) .......................(3)
where K = 1/ (4πεo ) is Coulomb's constant
Potential of final drop, Vf = K × [ ( 5q ) / R ] ........................... (4)
using eqn.(1) , Potential of final drop, Vf = K × [ ( 5q ) / (1.71 r ) ]
Vf = 0.585 × 5 × K × (q/r) ..................(5)
By comparing eqn.(3) and (5) , we see that Potential has decreased by a factor 0.585
Answered by Thiyagarajan K | 28 May, 2021, 11:01: PM
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