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CBSE Class 12-science Answered

question
Asked by tatsemsandhu3015 | 29 May, 2020, 11:34: AM
Expert Answer
Question: - The electric field and electric potential at any point due to a point charge kept in air is 20 NC-1 and 10 JC-1 respectively. Calculate the distance of the point from the charge and magnitude of the charge.
 
Solution: - 
E space equals space fraction numerator q over denominator 4 pi epsilon subscript 0 r squared end fraction space equals space 20 space N divided by C space
V space equals space fraction numerator q over denominator 4 pi epsilon subscript 0 r end fraction space equals space 10 space J divided by C space
T h u s comma space
r space equals space V over E space equals space 10 over 20 space equals space 0.5 space m space
T h u s comma space m a g n i t u d e space o f space c h a r g e space i s space
q space space equals space open parentheses 4 pi epsilon subscript 0 close parentheses V r thin space equals space fraction numerator 1 over denominator 9 cross times 10 to the power of 9 end fraction cross times 10 cross times 0.5 space equals space 0.55 space cross times 10 to the power of negative 9 end exponent space C space
 
P.S. -Dear user, if you need answer for rest of the questions then please ask them seperately in different post as only one question can be answered in each post. 

 

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