kindly solve this problem....

Asked by rajmantilakhlan | 9th Apr, 2020, 11:16: AM

Expert Answer:

It's given that, 
Fe = 0 and FG = 0
Thus, 
Fe = FG 
therefore fraction numerator 1 over denominator 4 pi epsilon subscript 0 end fraction fraction numerator increment e squared over denominator d squared end fraction equals fraction numerator G m squared over denominator d squared end fraction
rightwards double arrow 9 cross times 10 to the power of 9 open parentheses increment e squared close parentheses equals 6.67 cross times 10 to the power of negative 11 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent cross times 1.67 cross times 10 to the power of negative 27 end exponent
rightwards double arrow increment e squared equals fraction numerator 6.67 cross times 1.67 cross times 1.67 over denominator 9 end fraction cross times 10 to the power of negative 74 end exponent
rightwards double arrow increment e almost equal to 10 to the power of negative 37 end exponent C 
Correct option is (1) 

Answered by Shiwani Sawant | 9th Apr, 2020, 02:18: PM