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ICSE Class 10 Answered

Two boys weighing 60 kgf and 70 Kgf sit on one side of seesaw at distances of from the pivot of 1m and 1.2 m respectively where must a third boy of weight 80 kgf sit in order to balance them
Asked by Samrat | 30 Jun, 2018, 11:14: PM
answered-by-expert Expert Answer
Let the boy of 60 kgf is at left side and the other boy of 70 kgf is at right side.
Initially moment acting on right side is more. Hene to balance, the boy of 80 kgf should sit left side.
 
let the boy of 80kgf sits at a distance x from fulcrum.
 
then to balance the lever, we have,  60×1 + 80 × X = 70×1.2 ; we get X = 0.3 m
Answered by Thiyagarajan K | 01 Jul, 2018, 02:25: PM

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