ICSE Class 10 Answered
1000 Newton force is applied for 5 second on a body of mass 10 kg kept at rest.Find the change of momentum and distance travelled by the body during that time.
Asked by ayanpal713143 | 27 Nov, 2023, 09:32: PM
Expert Answer
F =1000 N
t = 5 s
m = 10 kg
F = m x a
a = F/m = 1000/10 = 100 m/s2
Change in momentum = Force x time = 1000 x 5 = 5000 Ns
Distance travelled by object during that time can be calculated using,
s = ut + 1/2 (at2) = (0) x (1/2) x 100 x (5)2 = 1250 m
Thus, change in momentum = 5000 Ns
and distance travelled during that time will be = 1250 m
Answered by Shiwani Sawant | 28 Nov, 2023, 10:13: AM
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