CBSE Class 11-science Answered
The vapour density of a volatile chloride of divalent metal is 59.5 and equivalent mass of metal is
Asked by Anil | 17 May, 2017, 02:36: PM
Expert Answer
Molecular formula of the compound is MCl2, where M is the divalent cation.
Vapour density (D) = Molecular mass (M) /2
So molar mass of the compound = 2 x 59.5 = 119
Equivalent mass (E) = molar mass (M) / (number of cation x valency)
Number of cation = 1, and valency of the cation =2
So, E = 119 / (1x2) = 59.5
Answered by Prachi Sawant | 17 May, 2017, 03:11: PM
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