CBSE Class 11-science Answered
ans with solutions
![question image](http://images.topperlearning.com/topper/new-ate/top_mob158234655117229169171da84342-ea05-4c8c-b128-5bec7d40c837.jpg)
Asked by anilsolanki2060 | 22 Feb, 2020, 10:12: AM
Option (A) is correct.
Given:
Density of CO2 = 0.44 g/cm−3
We know,
1 mole of CO2 = 6.022 × 1023 molecules
6.022 × 1023 molecules = 44 gm of CO2
Mass of one molecules of CO2 ![equals fraction numerator 44 over denominator 6.022 cross times 10 to the power of 23 end fraction](https://images.topperlearning.com/topper/tinymce/cache/cade5884d76df6851f0349c82523627f.png)
![equals fraction numerator 44 over denominator 6.022 cross times 10 to the power of 23 end fraction](https://images.topperlearning.com/topper/tinymce/cache/cade5884d76df6851f0349c82523627f.png)
![equals 44 over straight N space](https://images.topperlearning.com/topper/tinymce/cache/c828f5d7f34380843d4ff57ce7a3ce93.png)
Density ![equals Mass over Volume](https://images.topperlearning.com/topper/tinymce/cache/a0667fb1b3fbacbbefda59719c99cf1d.png)
![equals Mass over Volume](https://images.topperlearning.com/topper/tinymce/cache/a0667fb1b3fbacbbefda59719c99cf1d.png)
Volume
![equals Mass over Density
equals fraction numerator begin display style bevelled 44 over straight N end style over denominator 0.44 end fraction](https://images.topperlearning.com/topper/tinymce/cache/8959d8a794f3d8f1f4509a38ce8b6be0.png)
We have,
For critical volume
![space space space straight V subscript straight c equals space 3 cross times 4 over 3 πr cubed
fraction numerator begin display style bevelled 44 over N end style over denominator 0.44 end fraction equals space 3 cross times 4 over 3 cross times πr cubed
space space space space space space straight r cubed space equals space fraction numerator 44 over denominator 0.44 cross times 4 straight pi cross times straight N end fraction
space space space space space space straight r cubed space equals 25 over πN](https://images.topperlearning.com/topper/tinymce/cache/012d6c8ac0d6d16148d9fb9e0572d0fd.png)
Answered by Varsha | 24 Feb, 2020, 11:20: AM
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