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ICSE Class 10 Answered

the distance covered by a particle in time t is given by x=a+bt+ct2+dt3; find the dimensions of a.b.c and d. ([L], [LT-1], [lT-2], [LT-3])   please give the answer
Asked by defence | 16 Apr, 2019, 07:33: PM
answered-by-expert Expert Answer
I n space D i m e n s i o n space a n a l y s i s space w e space s t u d y space t h a t space f o r space a space e q u a t i o n space t o space b e space h o l d space v a l i d space i n space p h y s i c s space i t space m u s t space h a v e space a l l space t h e space q u a n t i t y space i n space s u m m a t i o n space a n d space s u b t r a c t i o n space i n space s a m e space d i m e n s i o n s space space S o space f o r space t h e space g i v e n space e q u a t i o n space i n space l e f t space h a n d space s i d e space w e space h a v e space q u a n t i t y space x space w h i c h space i s space m e a s u r e d space i n space m e t e r space s o space i t s space d i m e n s i o n s space m u s t space b e space I n space D i m e n s i o n space a n a l y s i s space w e space s t u d y space t h a t space f o r space a space e q u a t i o n space t o space b e space h o l d space v a l i d space i n space p h y s i c s space i t space m u s t space h a v e space a l l space t h e space q u a n t i t y space i n space s u m m a t i o n space a n d space s u b t r a c t i o n space i n space s a m e space d i m e n s i o n s space space S o space f o r space t h e space g i v e n space e q u a t i o n space i n space l e f t space h a n d space s i d e space w e space h a v e space q u a n t i t y space x space w h i c h space i s space m e a s u r e d space i n space m e t e r space s o space i t s space d i m e n s i o n s space m u s t space b e space open square brackets L close square brackets s o space t o space h o l d space t h i s space e q u a t i o n space v a l i d space t h e space q u a n t a t i e s space o n space t h e space r i g h t space s i d e space m u s t space h a v e space s a m e space d i m e n s i o n f o r space a space i t s space d i m e n s i o n space w o u l d space b e open square brackets L close square brackets space f o r space b space i t s space d i m e n s i o n space w o u l d space b e space fraction numerator open square brackets L close square brackets over denominator open square brackets T close square brackets end fraction equals space open square brackets L T to the power of negative 1 end exponent close square brackets f o r space c space i t s space d i m e n s i o n space w o u l d space b e space fraction numerator open square brackets L close square brackets over denominator open square brackets T squared close square brackets end fraction equals space open square brackets L T to the power of negative 2 end exponent close square brackets f o r space d space i t s space d i m e n s i o n space w o u l d space b e space fraction numerator open square brackets L close square brackets over denominator open square brackets T to the power of negative 3 end exponent close square brackets end fraction space equals space open square brackets L T to the power of negative 3 end exponent close square brackets
Answered by Ankit K | 17 Apr, 2019, 10:49: AM

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