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CBSE Class 10 Answered

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Asked by ABHILASHA | 16 Jan, 2019, 12:27: PM
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Area of Δ with vertices (x1, y1), (x2,y2) and (x3, y3) is (1/2)[ x1(y2-y3) + x2(y3-y1) +x3(y1-y2) ]
 
hence Area of Δ with vertices (a, b+c), (b, c+a) and (c, a+b)  is (1/2)[ a(c+a-a-b) + b(a+b-b-c) + c(b+c-c-a) ] = 0
Answered by Thiyagarajan K | 16 Jan, 2019, 03:19: PM

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