CBSE Class 10 Answered
solution for the first one
Asked by ABHILASHA | 16 Jan, 2019, 03:22: PM
Expert Answer
Possible Events
0+0 = 0 ; 0+1 =1 ; 0+6 = 6;
1+1 = 2 ; 1+6 =7 ;
6+6 = 12;
Hence different scores are :- 0, 1, 2, 6, 7, 12
Let a,b,c,d,e and f are 6 faces of a dice and markings are given below in a table
| a | b | c | d | e | f | |
| Dice-1 | 0 | 1 | 1 | 6 | 6 | 1 |
| Dice-2 | 0 | 1 | 1 | 6 | 6 | 1 |
to get total seven, possible face combinations are :-
{ b1+d2, b1+e2, c1+d2, c1+e2, d1+b2, d1+c2, d1+f2, e1+b2, e1+c2, e1+f2, f1+d2, f1+e2 }
In the above event tabulation, b1 means face-b of dice-1, c2 means face-c of dice-2. Similarly others are marked.
As given above, 12 combination out of 36 possible combination gives total 7.
Hence probability of getting 7 = 12/36 = 1/3
Answered by Thiyagarajan K | 16 Jan, 2019, 08:28: PM
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