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CBSE Class 10 Answered

solution for the first one
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Asked by ABHILASHA | 16 Jan, 2019, 03:22: PM
answered-by-expert Expert Answer
Possible Events
 
0+0 = 0   ;  0+1 =1 ;  0+6 = 6;
1+1 = 2  ;   1+6 =7 ;
6+6 = 12;
 
Hence  different scores are :-  0, 1, 2, 6, 7, 12
 
Let a,b,c,d,e and f are 6 faces of a dice and markings are given below in a table
 
  a b c d e f
Dice-1 0 1 1 6 6 1
Dice-2 0 1 1 6 6 1
to get total seven, possible face combinations are  :- 
{ b1+d2, b1+e2, c1+d2, c1+e2, d1+b2, d1+c2, d1+f2,  e1+b2, e1+c2, e1+f2, f1+d2, f1+e2 }
 
In the above event tabulation, b1 means face-b of dice-1, c2 means face-c of dice-2. Similarly others are marked.
 
As given above,  12 combination out of 36 possible combination gives total 7.
 
Hence probability of getting 7 = 12/36 = 1/3
Answered by Thiyagarajan K | 16 Jan, 2019, 08:28: PM
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