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NEET Class neet Answered

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Asked by 22bakugoku | 21 Apr, 2019, 05:23: PM
answered-by-expert Expert Answer
Latent heat of ice = m×l = 5×80 = 400cal
Latent heat of steam = 1×540 = 540cal
Here the heat release by steam is more so it will melt down ice completely but still 540-400 = 140 cal energy is left
This will increase the temperature of ice from 0 celcius
So let us assume final temperature to be T
So 5×1×T = 140+ 1×1×T
4T = 140
So T = 140/4 = 35 celcius 
Amount of water = 5+1 = 6gm
Answered by Ankit K | 21 Apr, 2019, 10:44: PM
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