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NEET Class neet Answered

how we find work done
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Asked by sujitjana971 | 18 Dec, 2022, 05:23: PM
answered-by-expert Expert Answer

Given that,

ΔQ=80 J

For mono atomic gas,

And for isobaric process (Constant pressure), ΔQ = nCpΔT and ΔW = nRΔT

Thus,

 capital delta W equals capital delta Q R divided by C subscript P equals 80 cross times R divided by left parenthesis 5 divided by 2 R right parenthesis equals 32 J

Now, according to first law of thermodynamics

ΔE =ΔQ – ΔW = 80 – 32 = 48 J

Answered by Jayesh Sah | 18 Dec, 2022, 08:11: PM
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