NEET Class neet Answered
Heat required to convert one gram of ice at 0 Celsius into steam at 100 Celsius
Asked by takshitashu46 | 09 Feb, 2022, 18:01: PM
Heat Q1 required to convert 1 g ice at 0o C to water at 0o C is given as
Q1 = m × Lf = 10-3 × 336 × 103 = 336 J ........................... (1)
where m is mass of ice , Lf is latent heat of fusion of ice .
Heat Q2 required to convert 1 g water at 0o C to water at 100o C is given as
Q2 = m × Cp × 100 = 10-3 × 4186 × 100 ≈ 419 J ...................... (2)
Heat Q3 required to convert 1 g water at 100o C to steam at 100o C is given as
Q3 = m × Lv = 10-3 × 2258 × 103 = 2258 J
Hence, total heat = Q1 + Q2 + Q3 = ( 336 + 419 + 2258 ) J = 3013 J
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