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CBSE Class 11-science Answered

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Asked by Prashant DIGHE | 04 Jun, 2020, 10:14: PM
answered-by-expert Expert Answer

                                                                N2O4(g)                                    2NO2(g)

At start                                                 100/92 = 1.08mol                                 0

At equilibrium                                       80/92 = 0.86                                 20/46 mol= 0.43 mol

                                      According to ideal gas equation, at two condition

At 300K                           P0V = n0RT0

                                         1 × V = 1.08 × R × 300      -------------- (i)

At 600K                        P1V = n1RT1

                                      P1 × V  = (0.86 + 0.43) × R ×600 ------------(ii)

Divide (ii) by (i)

P 1 space space equals space fraction numerator 1.29 space space cross times space space 600 space over denominator 1.08 space cross times space 300 space end fraction space space space space space space space space space space space space
space space space space space space space space space space space space space
space P 1 space equals space fraction numerator space 1.29 space space cross times space space 2 over denominator 1.08 end fraction space equals space space 2.38 space a t m space space space space space space space space space space space space space

Answered by Ravi | 05 Jun, 2020, 08:48: PM
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