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orce is applied on a body of mass 20 kg moving with a velocity of 40 ms-1. The body attains a velocity of 50 ms-1in 2 seconds. Calculate the work done by the body. orce is applied on a body of mass 20 kg moving with a velocity of 40 ms-1. The body attains a velocity of 50 ms-1in 2 seconds. Calculate the work done by the body. orce  is  applied  on  a body  of  mass  20  kg  moving  with  a  velocity  of  40  ms-1. The body attains a velocity of 50 ms-1in 2 seconds. Calculate the work done by the body.
Asked by senank123 | 18 Feb, 2019, 12:21: PM
answered-by-expert Expert Answer
acceleration = (final velocity - initial velocity)/ time = (50-40)/2 = 5 m/s2
 
Force acting on the body = mass×acceleration = 20×5 = 100 N
 
Distance travelled S  is obtained from formula " v2 = u2 + 2aS " , where v and u are initial and final veleocity, a is acceleration
 
Hence distance S = (502 - 402 )/(2×5) = 90 m
 
workdone = force × distance = 100×10 = 1000 J
Answered by Thiyagarajan K | 18 Feb, 2019, 12:35: PM

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