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CBSE Class 10 Answered

Let a,b,x,y be real numbers such that a^2 + b^2 = 81, x^2 + y^2 = 121 and ax + by = 99. Find the value of ay - bx.
Asked by acv27joy | 16 Dec, 2018, 04:39: PM
answered-by-expert Expert Answer
(ax+by)2 = a2x2 +b2y2+2abxy ................(1)
(ay-bx)2 = a2y2 +b2x2-2abxy ...................(2)
 
By adding (1) and (2), we get (ax+by)2 + (ay-bx)2 = (x2 + y2 )(a2 + b2 )
 
hence (ay-bx)2 = 121×81 - 9801 = 0    or   (ay - bx) = 0
Answered by Thiyagarajan K | 17 Dec, 2018, 06:31: AM

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