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ICSE Class 10 Answered

Jet fighter of mass 10000 kg has it take off velocity of 200 m per second in a distance of 1000 M find the force developed by the engine and its power  at the take off
Asked by Samrat | 30 Jun, 2018, 09:14: PM
answered-by-expert Expert Answer
We need to find acceleration to get force. Acceleration is obtained from " v2 = u2 +2 a S ", with initial velocity u =0
 
Acceleration = v2 /(2S) = (200×200)/(2×1000) = 20 m/s2
 
Force = mass×acceleration = 10000×20 = 2×105 N
Answered by Thiyagarajan K | 01 Jul, 2018, 08:17: PM

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