CBSE Class 10 Answered
In triangle abc angle b=90 bc+ab=17cm bc-ab=7cm find sin a cos c
Asked by Shaikmustafa | 13 Mar, 2019, 04:15: PM
Expert Answer
Let us use the notation side BC = a cm , AB = c cm
Given : c+a = 17 .................(1)
c -a = 7 ...................(2)
By adding both eqn., we get 2 c = 24 or c = 12 cm
By subtracting eqn.(2) from eqn.(1), we get 2 a = 10 or a = 5 cm
Then side AC = b =
sin(A) cos(C) = (5/13)(5/13) = 25/169
Answered by Thiyagarajan K | 13 Mar, 2019, 08:56: PM
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