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CBSE Class 10 Answered

 In a triangle ABC AB=8cm ,AC=10cm  and angleB=90° .A point P And Q are point on AB and AC respectively and PQ=2cm and angle PQA=90° find area of Triangle APQ  
Asked by samarsahu30 | 02 Dec, 2018, 12:41: PM
answered-by-expert Expert Answer
side BC = begin mathsize 12px style square root of A C squared minus A B squared end root space equals space square root of 10 squared minus 8 squared end root space equals space 6 space c m end style
Since triangles AQP and ABC both are right triangles and begin mathsize 12px style angle end styleA is common for both, they are similar triangles.
Hence begin mathsize 12px style fraction numerator A B over denominator A Q end fraction space equals space fraction numerator B C over denominator P Q end fraction equals fraction numerator A C over denominator A P end fraction end style
since (BC/PQ) = 3,  we have AQ = (8/3) cm
 
Area of Δ APQ = (1/2)×AQ×QP = (1/2)×(8/3)×2 = (8/3) cm2
Answered by Thiyagarajan K | 03 Dec, 2018, 02:29: AM

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