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CBSE Class 10 Answered

If zeba were younger by 5 years than what she really is,then the square of her age(in years) would have been 11 more than five times her actual age. What is her age now?
Asked by Akbaralvi1972 | 05 Mar, 2019, 08:07: PM
answered-by-expert Expert Answer
let actual age is x years
 
Given : square of ( actual age - 5 years) is 11 more than 5 times of her actual age, Hence  (x-5)2 = 5x+11 ......(1)
 
Eqn. (1) is simplified as,   x2 -10x +25 = 5x + 11   or   x2 -15x +14 = 0 .....................(2)
 
LHS of eqn.(2) is factorised and eqn.(2) is rewritten as,   (x-14)(x-1) = 0  ..............(3)
 
acceptable solution is x = 14.
 
Hence actualage is 14 years
Answered by Thiyagarajan K | 06 Mar, 2019, 12:19: AM

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