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How much maximum amount of Alumininum metal is deposited at cathode by passing one ampere current for 96500seconds through molten AlCl3?

Asked by sourabh7jain 7th June 2016, 11:41 AM
Answered by Expert
Answer:
Given:
c = 1 ampere
t = 96500 seconds
 
To find: Weight of Al deposited = ?
begin mathsize 12px style Solution colon straight e space equals space fraction numerator 27 over denominator 3 space cross times space 96500 end fraction Weight space of space Al space deposited space equals space equals space fraction numerator 27 space cross times space 1 space cross times space 96500 over denominator 3 space cross times space 96500 end fraction space equals space 9 space gm end style
 
Answered by Expert 9th June 2016, 12:04 PM
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