CBSE Class 12-science Answered
3.71 plz
![question image](https://images.topperlearning.com/topper/new-ate/topr_3656188416155212rps20190819230854.jpeg)
Asked by lovemaan5500 | 19 Aug, 2019, 23:13: PM
Given:
I = 25 ampere
Volume = 20 L
Mass of Cl2 = 1 kg
= 1000 gm
(i) Reactions taking place at electrodes:
Cathode: 2H2O + 2e− → H2(g) + 2OH−(aq)
Anode : 2Cl−(aq) → Cl2 + 2e−
(ii)
Mole of Cl2
![equals fraction numerator Mass over denominator Molar space mass end fraction
equals 1000 over 71
equals 14.08 space mol](https://images.topperlearning.com/topper/tinymce/cache/e14de7e44dcc29ffc39a7d9837374eac.png)
Electrons needed to carry out electrolysis = 2 × 14.08
= 28.16 mol
Quantity of electricity carried by these electrons = 28.16 × 96500 C
Time required,
Current efficiency is 62%
![straight I space equals 62 over 100 cross times 25
equals 15.5 space ampere](https://images.topperlearning.com/topper/tinymce/cache/877603d5bf5d5b40d477079313ac1e46.png)
![straight t equals straight Q over straight I
space equals fraction numerator 28.16 cross times 96500 over denominator 15.5 end fraction
space equals 175374.82 space straight s
equals space fraction numerator 175318.7 over denominator 3600 end fraction
space equals space 48.69 space hr](https://images.topperlearning.com/topper/tinymce/cache/23ea7c7365e99e117a7870fc4577b9f5.png)
(iii) Molarity of solution:
Amount of OH− ions released = 2× 14.08
= 28.16 mol
Molarity of OH− ions
![equals fraction numerator 28.16 over denominator 20 end fraction
equals space 1.408 space straight M](https://images.topperlearning.com/topper/tinymce/cache/c25b1500edafe7fb65be1f56d99a31f5.png)
Answered by Varsha | 20 Aug, 2019, 11:06: AM
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