CBSE Class 12-science Answered
3.57 plz
Asked by lovemaan5500 | 19 Aug, 2019, 11:11: PM
Expert Answer
Given:
E0Cu2+/Cu = 0.34 V
E0Ag2+/Ag = 0.80 V
R = 8.314 JK− mol−
F = 96500 C/mol
E0cell = E0cathode −E0anode
= 0.80 − 0.34
= 0.46 V
The net cell reaction,
Cu + 2Ag+ → Cu+ + 2Ag
n = 2
Nernst equation,
Cell potential is 0.3831 V
Answered by Varsha | 20 Aug, 2019, 03:49: PM
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