CBSE Class 11-science Answered
How much K2Cr2O7(mol.wt.=294.19) is required to prepare 1L of 0.1 M solution in acid medium
Asked by Anil | 17 May, 2017, 02:28: PM
Expert Answer
Equivalent of potassium dichromate
= Molar mass / 6
= 294.19/6
=49.30
For 0.1 N = 1/10 N
Weight of K2Cr2O7 required to prepare one litre 1/10 N
= Equivalent of potassium dichromate / 10
= 49.30 / 10
=4.93 g
Answered by Prachi Sawant | 17 May, 2017, 03:17: PM
Concept Videos
CBSE 11-science - Chemistry
Asked by drhimasingh | 22 May, 2020, 11:39: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by nareshrajpurohit43109 | 22 May, 2020, 11:18: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by d6knx7qmw1 | 15 May, 2020, 10:37: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by sahadipa1975 | 02 May, 2020, 08:53: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by abhishek19362771 | 08 Apr, 2020, 03:48: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by anilsolanki2060 | 22 Feb, 2020, 10:12: AM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by pujakurmi22 | 11 Nov, 2019, 10:59: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by jkatwara | 14 Oct, 2019, 12:21: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by vikas.kochhar6 | 30 Aug, 2019, 03:58: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by pb_ckt | 19 May, 2019, 11:56: PM
ANSWERED BY EXPERT