CBSE Class 10 Answered
from the top of a 30 M high building the angle of elevation of a tower is found to be equal to the angle of depression of the foot of the tower find the height of the tower
Asked by chinmayr633 | 15 Jan, 2019, 04:26: PM
Expert Answer
As shown in figure, from the top of building , angle of elevation ADC of top of tower is equal to
angle of depression CDB of foot of tower, then ΔADB is isoceless triangle and DC is peprpendicular to AB.
Hence BC = AC = 30 m.
Hence height of tower 60 m
Answered by Thiyagarajan K | 15 Jan, 2019, 08:30: PM
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