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CBSE Class 10 Answered

Find three consecutive terms in the AP whose sum is 15 and their product is 80( the terms are in ascending order)
Asked by prasadnaikwadi810 | 03 Feb, 2018, 08:55: PM
answered-by-expert Expert Answer

Let the AP be (a-d) , a (a+d)

by given

     (a-d) + a + (a-d) = 15

=> a- d+a+a +d  =15

=> 3a =15

=> a  =  5

A/q  (a-d) * a* (a+d) = 80

=>    a^2 - d^2 = 80/a = 80/5 = 16

=>    5^2 -d^2 = 16      => d^2 = 25-16 = 9 

=> d = 3 or -3 

When d = 3 

AP is : (a-d) ,a ,(a+d) = (5-3) , 5 , (5+3)

         = 2,5 , 8 . ans { since the is AP is in ascensing order , d = -3 is neglected }

Answered by Arun | 04 Feb, 2018, 08:47: AM

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