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electricity

Asked by yashpinto 18th May 2010, 11:42 PM
Answered by Expert
Answer:

Dear student,

As the resistors are in parallel,

I = I1+I2+I3

Resistors 1 and 2 are always connected, only the last resistor R3 is connected through a switch.

WHen, key is open, I = 0.6 Meas I1 = 0.6/2 = 0.3A, I2 = 0.6/2 = 0.3A

Now. when the key is closed, as the resistors are identical R3 = 0.3A, Hence total current flowing will be 0.3+0.3+0.3

 = 0.9 A

Hope this helps.

Team

Topperlearning.com

Answered by Expert 19th May 2010, 8:07 AM
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