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CBSE Class 11-science Answered

Dieldrin, an insecticide, contains C, H, Cl and O. Combustion of 29.72 mg of dieldrin gave 41.21 mg CO2 and 5.63 mg H2O. In a separate analysis 25.31 mg of dieldrin was converted into 57.13 mg AgCl. What is the empirical formula of dieldrin?
Asked by Rishav | 11 Mar, 2018, 01:23: AM
answered-by-expert Expert Answer
Given colon weight space of space Dieldrine space equals space 29.72 space mg Weight space of space CO subscript 2 space equals space 41.21 space mg Weight space of space straight H subscript 2 straight O equals space 5.63 space mg No. space of space carbon space atoms space equals space No space of space moles space of space CO subscript 2 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space As space 1 space mole space of space CO subscript 2 space space space space space space equals space 44 space therefore space 41.21 space equals apostrophe straight x apostrophe space moles space space space space space space space space space space space space space space space equals fraction numerator 41.21 over denominator 44 end fraction space space space space space space space space space space space space space equals 0.93 space moles space of space CO subscript 2 No. space of space moles space of space straight C equals space 0.93 No. space of space hydrogen space atoms space equals 2 space cross times No space of space moles space of space straight H subscript 2 straight O As space 1 space mole space of space space straight H subscript 2 straight O space space space space space space equals space 18 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 5.63 over denominator 18 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.31 space moles space of space straight H subscript 2 straight O No. space of space moles space of space straight H space equals 2 cross times space 0.31 space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.62 No. space of space moles space of space Cl space equals space 0.46 1 space mole space equals space 12 space straight g space of space Carbon 0.93 space moles space equals space fraction numerator 12 cross times 0.93 over denominator 1 end fraction space space space space space space space space space space space space space space space space space space space space equals 11.16 space straight g space of space straight C 1 space mole space equals space 1 space straight g space of space straight H 0.62 space moles space equals space 0.62 space straight g space of space straight H 1 space mole space equals space 35.5 space straight g space of space Cl 0.46 space moles space equals space 16.33 space straight g space of space Cl For space straight O space equals space 1.27 space ggm Calculating space no. space of space atoms comma straight C equals space 12 straight H equals space 8 Cl equals space 6 straight O equals 1 So space comma space the space empirical space formula space is space straight C subscript 12 straight H subscript 8 OCl subscript 6
Answered by Varsha | 11 Mar, 2018, 03:29: PM

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CBSE 11-science - Chemistry
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