CBSE Class 11-science Answered
Calculate the molality of aq. glucose solution in which mole fraction of glucose is 0.05
Asked by Anil | 12 May, 2017, 09:37: PM
Expert Answer
molality = (number of moles of solute/(kg of solvent)
If we have 0.05 mole of glucose solute and 0.95 mole of water, going off of the mole fractions.
1 mole of water = 18.015 g.
Hence ,0.95 moles of water has a mass of (0.95)(18.015 g)(1kg / 1000 g) = 0.01711 kg.
molality = 0.05 moles glucose / 0.01711 kg water = 2.92 mol/kg
Answered by Vaibhav Chavan | 13 May, 2017, 06:00: PM
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