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CBSE Class 10 Answered

 answer this ques....
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Asked by ABHILASHA | 01 Mar, 2019, 11:56: PM
answered-by-expert Expert Answer
Line passing through A(x1, y1) and B(x2 , y2) is given by,    begin mathsize 12px style y space minus space y subscript 1 space equals space fraction numerator y subscript 1 minus space y subscript 2 over denominator x subscript 1 minus space x subscript 2 end fraction open parentheses x space minus space x subscript 1 close parentheses space space.................... left parenthesis 1 right parenthesis end style
Hence line passing through (a, b+c) and (b, c+a) is  begin mathsize 12px style left parenthesis space y minus b minus c space right parenthesis equals space fraction numerator b plus c minus c minus a over denominator a minus b end fraction left parenthesis space x space minus space a right parenthesis space space equals space left parenthesis space a space minus space x space right parenthesis space space............ left parenthesis 2 right parenthesis end style
if the line given by eqn.(2) passes through (c, a+b) , then   ( a +b -b -c ) = ( a - c)  , which is true
 
Hence all the three points (a, b+c) , (b, c+a) and (c,a+b) are collinear
Answered by Thiyagarajan K | 02 Mar, 2019, 09:14: AM

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