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CBSE Class 10 Answered

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Asked by ABHILASHA | 02 Mar, 2019, 12:33: AM
answered-by-expert Expert Answer
Area of triangle with vertices A(x1 , y1 ) , B(x2 , y2 ) and C ( x3 , y3 )  = (1/2) [ x1 (y2 - y3 ) + x2 (y3 -y1) + x3(y1 - y2) ]
 
Hence Area of triangle with vertices (x, 4/3), (-2,6) and (3,1)  = (1/2)[ x(6-1) -2(1 -(4/3) +3( (4/3)-6) ) ] = 5
 
5x +(2/3) - 14 = 10   or  x = 14/3
Answered by Thiyagarajan K | 02 Mar, 2019, 01:01: PM
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