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ICSE Class 10 Answered

an athelete keeps himself fit by doing press ups.he applies a force of 300N as he pushes up to a distance of 0.5m.he does press ups in 30s.What is the average output in 30s?
Asked by Kanwaranita10 | 10 Jul, 2019, 08:29: PM
answered-by-expert Expert Answer
workdone = force×distance = 300 N × 05 m = 150 J
 
Rate of workdone = 150 J / 30 s = 5 W
 
Average power output in 30 s = 5 W
Answered by Thiyagarajan K | 10 Jul, 2019, 08:57: PM

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