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ICSE Class 10 Answered

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Asked by lovemaan5500 | 13 Mar, 2018, 07:17: AM
answered-by-expert Expert Answer
Heat gained by liquid of mass m1 and specific heat c1 = m1×c1×(t2-t1);
Heat gained by Calorimeter = H×(t2-t1)
Heat Loss of Solid of mass M = M×c2×(T-t2)
 
Heat Loss of Solid = Heat Gained by liquid and calorimeter;
m1×c1×(t2-t1)+H×(t2-t1) = M×c2×(T-t2)
 
hence begin mathsize 12px style H space equals M cross times c subscript 2 open parentheses fraction numerator T minus t subscript 2 over denominator t subscript 2 minus t subscript 1 end fraction close parentheses minus m subscript 1 c subscript 1 end style

Answered by Thiyagarajan K | 13 Mar, 2018, 01:34: PM

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