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Please solve this question 
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Asked by vikasg13.hardware | 23 Jun, 2018, 05:23: PM
answered-by-expert Expert Answer

The numbers are in the form of  (n + 3)(n + 2)(n + 1)n = 1000(n + 3) + 100 (n + 2) + 10 (n + 1) + n = 1111n + 3210 for 0 ≤ n ≤ 6

1111 ≡ 1 (mod37) and 3210 ≡ 28(mod37) So, 1111n  +3210 = n + 28 = 28, 29, 30, 31, 32, 33 and 34

The sum of remainders is 217.

Answered by Sneha shidid | 27 Jun, 2018, 09:34: AM

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