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CBSE Class 12-science Answered

8th a part plz
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Asked by lovemaan5500 | 08 Mar, 2020, 10:20: PM
answered-by-expert Expert Answer
To find the equations of tangent and normal to the curve x2/9 - y2/16 = 1 at (-3, 0)
 
T h e space c u r v e space i s x squared over 9 minus y squared over 16 equals 1 D i f f space w. r. t space x comma space w e space h a v e fraction numerator 2 x over denominator 9 end fraction minus fraction numerator 2 y over denominator 16 end fraction fraction numerator d y over denominator d x end fraction equals 0 rightwards double arrow fraction numerator d y over denominator d x end fraction equals fraction numerator 16 x over denominator 9 y end fraction open vertical bar fraction numerator d y over denominator d x end fraction close vertical bar subscript left parenthesis negative 3 comma space 0 right parenthesis end subscript equals 1 over 0 space S l o p e space o f space tan g e n t rightwards double arrow S l o p e space o f space n o r m a l space a t space left parenthesis negative 3 comma space 0 right parenthesis space equals 0 E q u a t i o n space o f space tan g e n t space a t space left parenthesis negative 3 comma space 0 right parenthesis space i s y minus 0 equals 1 over 0 open parentheses x plus 3 close parentheses rightwards double arrow x equals negative 3 space i s space t h e space e q u a t i o n space o f space tan g e n t E q u a t i o n space o s space n o r m a l space a t space left parenthesis negative 3 comma space 0 right parenthesis space i s y minus 0 equals 0 left parenthesis x plus 3 right parenthesis space rightwards double arrow y equals 0 rightwards double arrow x minus a x i s space i s space t h e space e q u a t i o n space o f space n o r m a l
Answered by Renu Varma | 09 Mar, 2020, 11:10: AM

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