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Show that the tangents to the curve y = 2x3 – 3 at the points where x = 2 and x = – 2 are parallel.
Asked by Topperlearning User | 07 Aug, 2014, 08:27: AM Expert Answer

The equation of the curve is y = 2x3 – 3     …(i)

Differentiating w.r.t. x, we get Now,   m1 = Slope of the tangent at and,     m2 = Slope of the tangent at Clearly, m1 = m2
Thus, the tangents to the given curve at the points where x = 2 and x = –2 are parallel.
Answered by | 07 Aug, 2014, 10:27: AM

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