Request a call back

Find the points on the curve y = x3 at which the slope of the tangent is equal to the y-coordinate of the point.
Asked by Topperlearning User | 07 Aug, 2014, 10:14: AM Expert Answer

Let the required point on the curve y = x3 be P(x1, y1).

We have, It is given that
Slope of the tangent at P(x1, y1) = Ordinate of P(x1, y1) Since (x1, y1) lies on y = x3. Therefore, Now, x1 = 0 Þ y1 = 0 and x1 = 3 Þ y1 = 33 = 27
Hence, required points are (0, 0) and (3, 27).
Answered by | 07 Aug, 2014, 12:14: PM

## Concept Videos

CBSE 12-science - Maths
Asked by agarwalgolu318 | 13 Aug, 2020, 08:09: PM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by givduf | 11 Jul, 2020, 09:00: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by sonalchoudhary882 | 22 Oct, 2018, 12:22: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 08:27: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 08:32: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 09:19: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 09:58: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 10:14: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 11 Aug, 2014, 10:06: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 12:43: PM ANSWERED BY EXPERT