Request a call back

The slope of the curve 2y2 = ax2 + b at (1, – 1) is – 1. Find a, b
Asked by Topperlearning User | 07 Aug, 2014, 08:32: AM Expert Answer

The equation of the curve is

2y2 = ax2 + b    …(i)
Differentiating w.r.t. x, we get  It is given that the slope of the tangent at (1, –1) is –1. Therefore, Since the point (1, –1) lies on (i). Therefore,
2 (–1)2 = a (1)2 + b Þ a + b = 2
Putting a = 2 in a + b = 2, we obtain b = 0.
Hence a = 2 and b = 0.
Answered by | 07 Aug, 2014, 10:32: AM

## Concept Videos

CBSE 12-science - Maths
Asked by agarwalgolu318 | 13 Aug, 2020, 08:09: PM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by givduf | 11 Jul, 2020, 09:00: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by sonalchoudhary882 | 22 Oct, 2018, 12:22: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 08:27: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 08:32: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 09:19: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 09:58: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 10:14: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 11 Aug, 2014, 10:06: AM ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by Topperlearning User | 07 Aug, 2014, 12:43: PM ANSWERED BY EXPERT