CBSE Class 12-science Answered
Find the points on the curve 9y2 = x3 where normal to the curve makes equal intercepts with the axes.
Asked by Topperlearning User | 07 Aug, 2014, 12:43: PM
Expert Answer
Let the required point be (x1, y1)
The equation of the curve is 9y2 = x2
Since (x1, y1) lies on the curve. Therefore,
Now, 9y2 = x3
Since the normal to the curve at (x1, y1) make equal intercepts with the coordinate axes. Therefore,
Slope of the normal = ± 1
Putting x1 = 0 in (i), we get
Putting x1 = 4 in (i), we get
But, the line making equal intercepts with the coordinate axes cannot pass through the origin.
Hence, the required points are 
Answered by | 07 Aug, 2014, 02:43: PM
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