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ICSE Class 10 Answered

When 4 hydrogen nuclei combine to form a Helium nucleus and the interior of the Sun The Loss in mass is 0.265 a.m.u. How much energy is released in (i)Mev(ii)joule.  
Asked by shrutsureja | 01 Oct, 2018, 06:34: PM
answered-by-expert Expert Answer
Energy equivalent of 1 atomic mass unit = 931.5 MeV = 1.492×10-10 J
 
Energy released = 0.265×931.5 = 247 MeV
                           = 0.265×1.492×10-10 = 0.395×10-10 J
Answered by Thiyagarajan K | 02 Oct, 2018, 11:42: PM

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