v=dx/dt I couldn't understand this formula. What is meant be dx and by dt?

Asked by arkabanerjee | 26th Aug, 2010, 06:38: PM

Expert Answer:

v = displacement/time = change in position/time = (x2 -  x1)/(t2 -  t1) = Δx/Δt 
But now consider Δt to be so small as 0.00000000001, which is approximately zero. We call this Δt tends to zero.
And since we are dealing with limiting case we change notation and just write it as dx/dt.
Now consider d/dt as an operator operating on x which is a function of t. And given any functional form for x we have to use rules of differentiation.
Regards,
Team,
TopperLeaning.

Answered by  | 26th Aug, 2010, 09:21: PM

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