v=dx/dt I couldn't understand this formula. What is meant be dx and by dt?
Asked by arkabanerjee | 26th Aug, 2010, 06:38: PM
v = displacement/time = change in position/time = (x2 - x1)/(t2 - t1) = Δx/Δt
But now consider Δt to be so small as 0.00000000001, which is approximately zero. We call this Δt tends to zero.
And since we are dealing with limiting case we change notation and just write it as dx/dt.
Now consider d/dt as an operator operating on x which is a function of t. And given any functional form for x we have to use rules of differentiation.
Answered by | 26th Aug, 2010, 09:21: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number