CBSE Class 11-science Answered
Q17. The velocity time relation of an electron starting from rest is given by v = kt where k = 6m / (s ^ 2) Calculate the distance traversed in 2 sec. 122
Asked by om636694 | 04 Mar, 2024, 09:10: PM
Expert Answer
Given velocity-time relation is
If we compare above expression with equation of motion " v = u + a t " ,
we get initial speed u = 0 and acceleration a = 6 m/s2.
Hence distance S traveled in 2 s is calculated from equation of motion " S = u t + (1/2) a t2 "with initial velocity u = 0 .
S = (1/2) a t2 = 1/2 × 6 × 2 × 2 = 12 m
Answered by Thiyagarajan K | 04 Mar, 2024, 11:11: PM
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